2n^2+9n+5=(n+4)*(2n+1)+1

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Solution for 2n^2+9n+5=(n+4)*(2n+1)+1 equation: 



2n^2+9n+5=(n+4)(2n+1)+1

We move all terms to the left:

2n^2+9n+5-((n+4)(2n+1)+1)=0

We multiply parentheses ..

2n^2-((+2n^2+n+8n+4)+1)+9n+5=0



We calculate terms in parentheses: -((+2n^2+n+8n+4)+1), so:

(+2n^2+n+8n+4)+1

We get rid of parentheses

2n^2+n+8n+4+1

We add all the numbers together, and all the variables

2n^2+9n+5

Back to the equation:

-(2n^2+9n+5)



We add all the numbers together, and all the variables

2n^2+9n-(2n^2+9n+5)+5=0

We get rid of parentheses

2n^2-2n^2+9n-9n-5+5=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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